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  1. Asked: February 1, 2022In:

    Match the Indian scientist’s name with contribution/discovery.

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    This answer was edited.

    The Indian scientists’ name have been correctly matched with their contributions/discoveries below: (i) J.C. Bose → (d) Ultrashort radio waves (ii) C.V. Raman → (f) Inelastic scattering of light by molecules (iii) M.N. Saha → (a) Thermal ionization (iv) S.N. Bose → (c) Quantum statistics (v) H.J. BhRead more

    The Indian scientists’ name have been correctly matched with their contributions/discoveries below:
    (i) J.C. Bose → (d) Ultrashort radio waves
    (ii) C.V. Raman → (f) Inelastic scattering of light by molecules
    (iii) M.N. Saha → (a) Thermal ionization
    (iv) S.N. Bose → (c) Quantum statistics
    (v) H.J. Bhabha → (b) Cosmic radation and nuclear weapons
    (vi) S. Chandrasekhar → (e) Structure and evolution of stars
    (i ) – (d); (ii) – (f); (iii) – (a); (iv) – (c); (v) – (b); (vi) – (e).

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  2. Asked: January 31, 2022In:

    Match the scientist’s name with the contribution/discovery.

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    The scientists' name have been correctly matched with their contributions/discoveries below: (i) Faraday → (g) Law of electromagnetic induction (ii) Rutherford → (j) Nuclear model of atom (iii) Chadwick → (i) Neutron (iv) Bohr → (b) Quantum model of hydrogen atom (v) Newton → (a) Law of gravitation,Read more

    The scientists’ name have been correctly matched with their contributions/discoveries below:

    (i) Faraday → (g) Law of electromagnetic induction
    (ii) Rutherford → (j) Nuclear model of atom
    (iii) Chadwick → (i) Neutron
    (iv) Bohr → (b) Quantum model of hydrogen atom
    (v) Newton → (a) Law of gravitation, Laws of motion
    (vi) Maxwell → (c) Unification of light and electromagnetism
    (vii) Salam → (f) Unification of weak and electromagnetic interactions
    (viii) Einstein → (h) Theory of relativity, Explanation of photoelectric effect
    (ix) Roentgen → (e) X-rays
    (x) Madam Curie → (n) Discovery of radium
    (xi) J. J. Thomson → (m) Electron
    (xii) de Broglie → (k) Wave nature of matter
    (xiii) John Bardeen → (l) Transistor
    (xiv) Hubble → (h) Expansion of the universe

    (i ) – (g); (ii) – (j); (iii) – (i); (iv) – (b); (v) – (a); (vi) – (c); (vii) – (f); (viii) – (d); (ix) – (e); (x) – (n); (xi) – (m); (xii) – (k); (xiii) – (l); (xiv) – (h).

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  3. Asked: January 31, 2022In:

    Explain, with example, the conversion of nucleons.

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    In any nuclear reaction, the number of nucleons remains unchanged. The radioactive decay of uranium nucleus is: 92U238 → 90Th234 + 2He4 The total number of nucleons is 238 before as well as after the decay.

    In any nuclear reaction, the number of nucleons remains unchanged. The radioactive decay of uranium nucleus is:

    92U238 → 90Th234 + 2He4

    The total number of nucleons is 238 before as well as after the decay.

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  4. Asked: July 6, 2021In:

    Total number of atoms represented by the compound CuS04.5H20

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    In CuSO4.5H2O, we have: 1 Copper (Cu) atom, 1 Sulphur (S) atom, 4 Oxygen (O) atoms, 5*2 = 10 Hydrogen (H) atoms, and 5*1 = 5 Oxygen (O) atoms. Thus, in total, the number of atoms present in the compound is: 1+1+4+10+5 = 21.

    In CuSO4.5H2O, we have:
    1 Copper (Cu) atom,
    1 Sulphur (S) atom,
    4 Oxygen (O) atoms,
    5*2 = 10 Hydrogen (H) atoms,
    and 5*1 = 5 Oxygen (O) atoms.

    Thus, in total, the number of atoms present in the compound is: 1+1+4+10+5 = 21.

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