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  1. Best Answer

    In CuSO4.5H2O, we have: 1 Copper (Cu) atom, 1 Sulphur (S) atom, 4 Oxygen (O) atoms, 5*2 = 10 Hydrogen (H) atoms, and 5*1 = 5 Oxygen (O) atoms. Thus, in total, the number of atoms present in the compound is: 1+1+4+10+5 = 21.

    In CuSO4.5H2O, we have:
    1 Copper (Cu) atom,
    1 Sulphur (S) atom,
    4 Oxygen (O) atoms,
    5*2 = 10 Hydrogen (H) atoms,
    and 5*1 = 5 Oxygen (O) atoms.

    Thus, in total, the number of atoms present in the compound is: 1+1+4+10+5 = 21.

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  2. Best Answer

    The scientists' name have been correctly matched with their contributions/discoveries below: (i) Faraday → (g) Law of electromagnetic induction (ii) Rutherford → (j) Nuclear model of atom (iii) Chadwick → (i) Neutron (iv) Bohr → (b) Quantum model of hydrogen atom (v) Newton → (a) Law of gravitation,Read more

    The scientists’ name have been correctly matched with their contributions/discoveries below:

    (i) Faraday → (g) Law of electromagnetic induction
    (ii) Rutherford → (j) Nuclear model of atom
    (iii) Chadwick → (i) Neutron
    (iv) Bohr → (b) Quantum model of hydrogen atom
    (v) Newton → (a) Law of gravitation, Laws of motion
    (vi) Maxwell → (c) Unification of light and electromagnetism
    (vii) Salam → (f) Unification of weak and electromagnetic interactions
    (viii) Einstein → (h) Theory of relativity, Explanation of photoelectric effect
    (ix) Roentgen → (e) X-rays
    (x) Madam Curie → (n) Discovery of radium
    (xi) J. J. Thomson → (m) Electron
    (xii) de Broglie → (k) Wave nature of matter
    (xiii) John Bardeen → (l) Transistor
    (xiv) Hubble → (h) Expansion of the universe

    (i ) – (g); (ii) – (j); (iii) – (i); (iv) – (b); (v) – (a); (vi) – (c); (vii) – (f); (viii) – (d); (ix) – (e); (x) – (n); (xi) – (m); (xii) – (k); (xiii) – (l); (xiv) – (h).

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  3. The correct answers are 25 and 67. This is because: 25 divided by 3 leaves a remainder of 1 25 divided by 7 leaves a remainder of 4 67 divided by 3 leaves a remainder of 1 67 divided by 7 leaves a remainder of 4

    The correct answers are 25 and 67.

    This is because:

    25 divided by 3 leaves a remainder of 1
    25 divided by 7 leaves a remainder of 4
    67 divided by 3 leaves a remainder of 1
    67 divided by 7 leaves a remainder of 4

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    • 0
  4. Best Answer

    The answer is 17 (Seventeen). Explanation: It's given that - P is a date in the month of October Q is a date in the month of November. P and Q both are perfect squares. Perfect squares are numbers whose square root is a natural number, including 0. The available dates in October that are perfect numRead more

    The answer is 17 (Seventeen).

    Explanation:
    It’s given that –
    P is a date in the month of October
    Q is a date in the month of November.

    P and Q both are perfect squares.

    Perfect squares are numbers whose square root is a natural number, including 0.

    The available dates in October that are perfect numbers are:

    1*1 = 1st October
    2*2 = 4th October
    3*3 = 9th October
    4*4 = 16th October, and
    5*5 = 25th October

    It’s mentioned that Pth October and Qth November are only 10 days apart.

    As all the perfect square dates before 25th October do not occur 10 days before any date of November, the only choice we’re left with is 25th October.

    10 days after 25th October comes 4th November.

    here, both 25 and 4 are perfect squares.

    thus, P = 25 and Q = 4.

    Now, P – 2Q = 25 – 2(4) = 25 – 8 = 17 (Required Answer).

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  5. Interferons are low molecular weight proteins produced by virus infected cells. They protect non-infected cells from further infections.

    Interferons are low molecular weight proteins produced by virus infected cells. They protect non-infected cells from further infections.

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  6. Virus infected cells secrete proteins called interferons which non-infected cells from further viral infection.

    Virus infected cells secrete proteins called interferons which non-infected cells from further viral infection.

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  7. Chikungunya and Dengue Fever are two diseases that can be controlled by eradication of Aedes Mosquito.

    Chikungunya and Dengue Fever are two diseases that can be controlled by eradication of Aedes Mosquito.

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  8. To ensure anamnestic or secondary immune response, dead or attenuated pathogens of a disease can be injected into a healthy person that can produce memory cells i.e., vaccination.

    To ensure anamnestic or secondary immune response, dead or attenuated pathogens of a disease can be injected into a healthy person that can produce memory cells i.e., vaccination.

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